Question

Pinky is standing in a queue at a ticket counter. Suppose the ratio of the number of persons standing ahead of Pinky to the number of persons standing behind her in the queue is $3 : 5$. If the total number of persons in the queue is less than 300, then the maximum possible number of persons standing ahead of Pinky is

Accepted Answer

111. Let the number of persons standing ahead of Pinky be $3k$ and behind her be $5k$. Total number of persons in the queue $= 3k + 5k + 1 = 8k + 1$ (including Pinky). We are given: $$8k + 1 < 300$$ $$8k < 299$$ $$k < 37.375$$ Since $k$ is an integer, the maximum value of $k$ is $37$. The maximum possible number of persons standing ahead of Pinky is: $$3k = 3 	imes 37 = 111$$

Maximum Persons Standing Ahead in Queue

Explanation

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