Shift and Ratio of Students

CAT 2025 Slot 1 · Quantitative Ability · Medium · Ratio and Proportion

This is a medium Quantitative Ability question from the CAT 2025 Slot 1 paper. It tests Ratio and Proportion. The full answer key and a step-by-step explanation are below — try it yourself first, then reveal the solution.

The ratio of the number of students in the morning shift and afternoon shift of a school was 13:913 : 9. After 2121 students moved from the morning shift to the afternoon shift, this ratio became 19:1419 : 14. Next, some new students joined the morning and afternoon shifts in the ratio 3:83 : 8 and then the ratio of the number of students in the morning shift and the afternoon shift became 5:45 : 4. The number of new students who joined is

  1. A.

    110

  2. B.

    121

  3. C.

    88

  4. D.

    99

Answer

D

Explanation

Let initial morning and afternoon students be 13x13x and 9x9x. After 2121 students moved: 13x219x+21=1914\frac{13x - 21}{9x + 21} = \frac{19}{14} 14(13x21)=19(9x+21)14(13x - 21) = 19(9x + 21) 182x294=171x+399    11x=693    x=63182x - 294 = 171x + 399 \implies 11x = 693 \implies x = 63

So, after the move: Morning =13(63)21=81921=798= 13(63) - 21 = 819 - 21 = 798 Afternoon =9(63)+21=567+21=588= 9(63) + 21 = 567 + 21 = 588

Let new students joining be 3k3k and 8k8k (total =11k= 11k): 798+3k588+8k=54\frac{798 + 3k}{588 + 8k} = \frac{5}{4} 4(798+3k)=5(588+8k)4(798 + 3k) = 5(588 + 8k) 3192+12k=2940+40k    28k=252    k=93192 + 12k = 2940 + 40k \implies 28k = 252 \implies k = 9

Total new students =11k=11×9=99= 11k = 11 \times 9 = 99.

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