Ratio identity given A:B = C:D

CMAT 2021 · Quantitative Techniques & Data Interpretation · Easy · Ratio and Proportion

If A:B=C:DA : B = C : D, then the value of A2+B2C2+D2\frac{A^2 + B^2}{C^2 + D^2} is

  1. A.

    1/2

  2. B.

    (A+B)/(C+D)

  3. C.

    (A-B)/(C-D)

  4. D.

    (AB)/(CD)

Answer

D

Explanation

Let AB=CD=k  ⟹  A=Bk,C=Dk\frac{A}{B} = \frac{C}{D} = k \implies A = Bk, C = Dk.

A2+B2C2+D2=B2k2+B2D2k2+D2=B2(k2+1)D2(k2+1)=B2D2\frac{A^2 + B^2}{C^2 + D^2} = \frac{B^2 k^2 + B^2}{D^2 k^2 + D^2} = \frac{B^2 (k^2 + 1)}{D^2 (k^2 + 1)} = \frac{B^2}{D^2}

Also check A×BC×D=(Bk)×B(Dk)×D=B2kD2k=B2D2\frac{A \times B}{C \times D} = \frac{(Bk) \times B}{(Dk) \times D} = \frac{B^2 k}{D^2 k} = \frac{B^2}{D^2}.

Thus, A2+B2C2+D2=A×BC×D\frac{A^2 + B^2}{C^2 + D^2} = \frac{A \times B}{C \times D}.

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