Greatest Integer Function Identity

CAT 2025 Slot 1 · Quantitative Ability · Hard · Functions

Let 3≤x≤63 \le x \le 6 and [x2]=[x]2[x^2] = [x]^2, where [x][x] is the greatest integer not exceeding xx. If set SS represents all feasible values of xx, then a possible subset of SS is

  1. A.

    (4,18)∪[5,27)∪{6}(4, \sqrt{18}) \cup [5, \sqrt{27}) \cup \{6\}

  2. B.

    (3,10)∪[4,17)∪{6}(3, \sqrt{10}) \cup [4, \sqrt{17}) \cup \{6\}

  3. C.

    (3,10)∪[5,26)∪{6}(3, \sqrt{10}) \cup [5, \sqrt{26}) \cup \{6\}

  4. D.

    [3,10]∪[5,26][3, \sqrt{10}] \cup [5, \sqrt{26}]

Answer

C

Explanation

Analyze interval by interval for integer n=[x]n = [x]:

  • For n=3n = 3: x∈[3,4)x \in [3, 4), [x]2=9[x]^2 = 9. We need [x2]=9  ⟹  9≤x2<10  ⟹  3≤x<10[x^2] = 9 \implies 9 \le x^2 < 10 \implies 3 \le x < \sqrt{10}.
  • For n=4n = 4: x∈[4,5)x \in [4, 5), [x]2=16[x]^2 = 16. We need [x2]=16  ⟹  16≤x2<17  ⟹  4≤x<17[x^2] = 16 \implies 16 \le x^2 < 17 \implies 4 \le x < \sqrt{17}.
  • For n=5n = 5: x∈[5,6)x \in [5, 6), [x]2=25[x]^2 = 25. We need [x2]=25  ⟹  25≤x2<26  ⟹  5≤x<26[x^2] = 25 \implies 25 \le x^2 < 26 \implies 5 \le x < \sqrt{26}.
  • For x=6x = 6: [62]=36=[6]2[6^2] = 36 = [6]^2, so x=6x = 6 is included. Comparing options, (3,10)∪[5,26)∪{6}(3, \sqrt{10}) \cup [5, \sqrt{26}) \cup \{6\} is a valid subset of SS.

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