95th Term of Repeating Letter Series

Number of terms for each letter: A has 2, B has 4, C has 6, D has 8, ... This is an AP: $2, 4, 6, 8, \dots, 2n$. Sum of first $n$ terms = $n(n+1)$. For $n = 9$, sum = $9 \times 10 = 90$ terms (up to letter I). For $n = 10$, sum = $10 \times 11 = 110$ terms (up to letter J). Since 95 lies between 91 and 110, the 95th term is J.