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Data Interpretation: University Student Majors

XAT 2019 · Quantitative Ability & Data Interpretation · Medium · Data Interpretation

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Passage / data set

The break-up of the students in a university by subject major is given in the polar pie-chart. The bar chart shows the number of students who major in physics by geographic location.

Subject Breakdown (Pie Chart):

  • Physics: 18%
  • Chemistry: 14%
  • Mathematics: 16%
  • Economics: 12%
  • Engineering: 20%
  • History: 10%
  • Others: 10%

Physics Majors by Location (Bar Chart):

  • Delhi: 18
  • Mumbai: 36
  • Kolkata: 80
  • Chennai: 40
  • Hyderabad: 23
  • Others: 28

Question 1 of 3

How many students major in chemistry?

  1. A.

    200

  2. B.

    175

  3. C.

    170

  4. D.

    190

  5. E.

    180

Answer

B

Explanation

Total Physics majors =18+36+80+40+23+28=225= 18 + 36 + 80 + 40 + 23 + 28 = 225. Since Physics represents 18%18\% of total students, Total Students =2250.18=1250= \frac{225}{0.18} = 1250. Chemistry majors =14% of 1250=0.14×1250=175= 14\% \text{ of } 1250 = 0.14 \times 1250 = 175.

Question 2 of 3

If the proportion of physics majors who are from Delhi is the same as the proportion of engineering majors who are from Delhi, how many engineering majors are from Delhi?

  1. A.

    22

  2. B.

    26

  3. C.

    18

  4. D.

    20

  5. E.

    24

Answer

D

Explanation

Proportion of Physics majors from Delhi =18225=225= \frac{18}{225} = \frac{2}{25}. Total Engineering majors =20% of 1250=250= 20\% \text{ of } 1250 = 250. Engineering majors from Delhi =225×250=20= \frac{2}{25} \times 250 = 20.

Question 3 of 3

12% of all students are from Chennai. What is the largest possible percentage of economics students that can be from Chennai, rounded off to the nearest integer?

  1. A.

    73%

  2. B.

    77%

  3. C.

    75%

  4. D.

    71%

  5. E.

    69%

Answer

A

Explanation

Total students from Chennai =12% of 1250=150= 12\% \text{ of } 1250 = 150. Physics students from Chennai =40= 40. Remaining Chennai students =150−40=110= 150 - 40 = 110. Total Economics students =12% of 1250=150= 12\% \text{ of } 1250 = 150. Maximum possible Economics students from Chennai =110= 110. Percentage =110150×100%=73.33%≈73%= \frac{110}{150} \times 100\% = 73.33\% \approx 73\%.

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