Multiples of 125 by 10 or 15

Initial number $= 125 = 5^3$. In each step, we multiply by $10 = 2^1 \times 5^1$ or $15 = 3^1 \times 5^1$. Let $a$ be the power of 2 and $b$ be the power of 3 added. Total multiplications $= a + b$. Then power of 5 becomes $3 + a + b$. Thus, for any valid resultant number $2^a 3^b 5^c$, we must have: $c - (a + b) = 3$

Checking Option D: $1034 - (476 + 455) = 1034 - 931 = 103 \neq 3$. Hence, Option D cannot be a resultant number.