Possible value of quadratic expression coefficients

CAT 2019 Slot 2 · QA · Hard · Linear & quadratic equations

The quadratic equation x2+bx+c=0x^2 + bx + c = 0 has two roots 4a4a and 3a3a, where aa is an integer. Which of the following is a possible value of b2+cb^2 + c?

  1. A.

    3721

  2. B.

    549

  3. C.

    361

  4. D.

    427

Answer

B

Explanation

For x2+bx+c=0x^2 + bx + c = 0 with roots 4a4a and 3a3a:

  • Sum of roots =4a+3a=7a=b    b=7a= 4a + 3a = 7a = -b \implies b = -7a
  • Product of roots =(4a)(3a)=12a2=c= (4a)(3a) = 12a^2 = c

Then: b2+c=(7a)2+12a2=49a2+12a2=61a2b^2 + c = (-7a)^2 + 12a^2 = 49a^2 + 12a^2 = 61a^2

Since aa is an integer, b2+cb^2 + c must be 61 times a perfect square. Check 549: 54961=9=32    a=3\frac{549}{61} = 9 = 3^2 \implies a = 3 Thus 549 is a possible value.

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